[supreme] py GATHERING USER NAME OR LEECHING INSTA USER NAMES SIMPLE PY scrpit

[mesvak 362]

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#usage:open cmd > type : pip install selenium    // you can edit this shit and do it as u want 
#go to "http://chromedriver.chromium.org/downloads" and download the ChromeDriver which matches with your      version
#for finding your chrome version you have to check it at "chrome://settings/help" in your chrome browser
#then replace the downloaded ChromeDriver path to the marked line in the code

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
import time

#requirements //mesvak is here XD
n = input('How many users do you want to gather ? ')
u = input("username: ")
p = input("password: ")
t = input("Who is your target(id instagram): ")
f= open("targets.txt","w")

#$$$$$$$$$$$$$$$$$$$$$$$
chromedriver = "C:/mesvak/.../Downloads/chromedriver.exe" #replace the path here 
#$$$$$$$$$$$$$$$$$$$$$$$

driver = webdriver.Chrome(chromedriver)
url = "https://instagram.com/"+t+"/followers"
driver.get(url)
time.sleep(4)
driver.find_element_by_name("username").send_keys(u)
driver.find_element_by_name("password").send_keys(p)
time.sleep(2)
driver.find_element(By.XPATH, "//*[@id='react-root']/section/main/div/article/div/div[1]/div/form/div[4]/button").click()
time.sleep(10)
#Gathering steps
x = 1
y = int(n)+1
while x != y:
   prof = "/html/body/div[3]/div/div[2]/ul/div/li["+str(x)+"]/div/div[1]/div[2]/div[1]/a"
   u_name = "/html/body/div[3]/div/div[2]/ul/div/li["+str(x)+"]/div/div[1]"
   sc = driver.find_element(By.XPATH, "/html/body/div[3]/div/div[2]/ul/div/li["+str(x)+"]/div")
   sc.location_once_scrolled_into_view
   sc.location_once_scrolled_into_view
   name = driver.find_element(By.XPATH, u_name).find_element(By.XPATH, prof)
   time.sleep(1)
   name.location_once_scrolled_into_view
   time.sleep(1)
   res = name.get_attribute("href")
   f.write(res[26:-1]+"\n")
   print(res[26:-1]+" "+str(x)+"\n")
   x = x + 1
print("happy days nigga u have ur own shit kappa")
f.close()

 

 

 

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[ondrills 4]

I'm interested but idk what if it is what I think it is

[THEMONYO 2]

thanks mate

[toffife 2]

ty for sharing